Twostep equations – word problems
Simply put, twostep equations – word problems are two step equations expressed using words instead of just numbers and mathematical symbols. They are just a bit more complicated than onestep equations with word problems and they demand just a bit more effort to solve. If you are not confident in your abilities to solve twostep equations with word problems, you can go to onestep equations – word problems and practice some more before continuing with this lesson. But if you feel ready, we will show you how to solve it using this example:
Hermione’s Bikes rents bikes for $10 plus $4per hour. Janice paid $30 to rent a bike. For how many hours did she rent the bike?
First thing we have to do in this assignment is to find the variable and see what its connection is with the other values. The thing we do not know is the number of hours Janice rented the bike for and we have been asked to find that out. That means the number of hours is our variable.
The cost of renting a bike is 10$ to take the bike and 4$ for every hour it spends in our possession. The final sum Janice paid is $30. Let us write that down as an equation.
4 * x + 10 = 30
Now, in order to make things neater and more clear, let us move all the numbers (except for the number 4 – we have to get rid of it in a different way) to the right side of the equation. Like this:
4 * x = 30 – 10
To simplify things further, let us perform the subtraction.
4 * x = 20
The next thing to do is to get rid of the number 4 in front of the variable. We will do that by dividing the whole equation by 4.
4 * x = 20 :4
x = 5
Now that we have calculated the value of the variable, we can tell that Janice rented that bike for 5 hours. If you want to check the result – you can. If you multiply $4 that Janice paid per hour by the 5 hours she spend with that bike and then add the $10 she had to pay regardless of the time she spent with the bike, you will get a total sum of $30 that is indeed the full sum she paid.
These word problems are called twostep because you have to perform two mathematical operations in order to solve them. In this case – addition (subtraction) and multiplication (division). To practice solving twostep equations – word problems, feel free to use the worksheets below.
Twostep equations – word problems exams for teachers
Exam Name  File Size  Downloads  Upload date 
Integers


Twostep equations – Word problems – Integers – very easy  0 B  39150  January 1, 1970 
Twostep equations – Word problems – Integers – easy  0 B  37024  January 1, 1970 
Twostep equations – Word problems – Integers – medium  0 B  51260  January 1, 1970 
Twostep equations – Word problems – Integers – hard  0 B  27545  January 1, 1970 
Twostep equations – Word problems – Integers – very hard  0 B  17231  January 1, 1970 
Decimals


Twostep equations – Word problems – Decimals – very easy  0 B  4851  January 1, 1970 
Twostep equations – Word problems – Decimals – easy  0 B  5839  January 1, 1970 
Twostep equations – Word problems – Decimals – medium  0 B  8488  January 1, 1970 
Twostep equations – Word problems – Decimals – hard  0 B  8351  January 1, 1970 
Twostep equations – Word problems – Decimals – very hard  0 B  6241  January 1, 1970 
Twostep equations – word problems worksheets for students
Worksheet Name  File Size  Downloads  Upload date 
Twostep equations – Word problems – Integers  0 B  40109  January 1, 1970 
Twostep equations – Word problems – Decimals  0 B  11480  January 1, 1970 